anybody can solve it
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here given that
in triangle ABC
AB = BC
angle B = 80°
SO
A+B+C = 180° In triangle
thus
AB= BC ,
SO
angle a = angle C
Now
A+ B+C = 180°
2A+ B = 180°
2A + 80° = 180°
2A =180°- 80°
2A = 100°
A = 50° Ans
Hope it's helpful ✌✌
in triangle ABC
AB = BC
angle B = 80°
SO
A+B+C = 180° In triangle
thus
AB= BC ,
SO
angle a = angle C
Now
A+ B+C = 180°
2A+ B = 180°
2A + 80° = 180°
2A =180°- 80°
2A = 100°
A = 50° Ans
Hope it's helpful ✌✌
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