Math, asked by shubham13613, 1 year ago

anybody can solve it

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faraanahmedhashmi: very easy question
faraanahmedhashmi: answer is p^2 + 1/ p ^ 2 -1
shubham13613: how solve it bro
shubham13613: i didn't understand...
faraanahmedhashmi: use the identity sec^2 a - tan^2a = 1
faraanahmedhashmi: then factorise it into a-b and a+ b

Answers

Answered by HitakshiHK816
0

this is your answer....

plz mark it as brainlist

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faraanahmedhashmi: you should have just subtracted the equation.
HitakshiHK816: koi bhi sum ek se jyada methods se solve ho sakta hai.....
HitakshiHK816: there's nothing wrong
faraanahmedhashmi: baat wrong aur right ki nahi hai baat hai time management ki
faraanahmedhashmi: my advice always try to figure out the shortest way to solve any problem
Answered by faraanahmedhashmi
0

Answer:

hi mate

Step-by-step explanation:

given,  secФ+tanФ=p     -( 1 )

now,  sec²Ф - tan²Ф =1  using the identity

[secФ-tanФ][secФ+tanФ] =1         [ a²-b²=(a-b)(a+b) ]

(secФ - tanФ)×p =1      [ putting the value of secФ+tanФ=p ]

secФ - tanФ = 1/p     - (2)

now adding and subtracting 1 and 2 we get

by adding,

2secФ = p+1/p

2secФ= p² +1/p   - (3)

and by subtracting,

2tanФ = p-1/p

2tanФ= p²-1/p   (4)

dividing 3 and 4 we get,

2secФ/2tanФ= p²+1/p²-1    

cosecФ = p²+1/p²-1     [ 1/cos * cos/sin ]


faraanahmedhashmi: please mark as brainliest
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