anybody can solve it
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faraanahmedhashmi:
very easy question
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this is your answer....
plz mark it as brainlist
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hi mate
Step-by-step explanation:
given, secФ+tanФ=p -( 1 )
now, sec²Ф - tan²Ф =1 using the identity
[secФ-tanФ][secФ+tanФ] =1 [ a²-b²=(a-b)(a+b) ]
(secФ - tanФ)×p =1 [ putting the value of secФ+tanФ=p ]
secФ - tanФ = 1/p - (2)
now adding and subtracting 1 and 2 we get
by adding,
2secФ = p+1/p
2secФ= p² +1/p - (3)
and by subtracting,
2tanФ = p-1/p
2tanФ= p²-1/p (4)
dividing 3 and 4 we get,
2secФ/2tanФ= p²+1/p²-1
cosecФ = p²+1/p²-1 [ 1/cos * cos/sin ]
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