Question

anybody give answer of this question.

Answer 1

$( \frac{16}{81} ) {}^{4} \div ( \frac{32}{243} ) \\ = ( \frac{2 {}^{4} }{3 {}^{4} }) {}^{4} \div ( \frac{2 {}^{5} }{3 {}^{5} }) \\ = (\frac{2}{3} ) {}^{4 \times 4} \div (\frac{2}{3} ) {}^{5} \\ = (\frac{2}{3} ) {}^{16} \div ( \frac{2}{3} ) {}^{5} \\ when \: bases \: are \: same \: in \: division \: \\ form \: we \: subtract \: powers. so \\ =( \frac{2}{3} ) {}^{16 - 5} \\ = ( \frac{2}{3} ) {}^{11} \\ = \frac{2048}{177147}$

Answer 2

Hey dear!

Here is yr answer.....

=> (16/81)^4 ÷ (32/243)

=> [(2/3)^4]^4 × (243/32)

=> (2/3)^16 × (3/2)^5

=> (2/3)^11

=> 2048/177147

Hope it hlpz...