Question

ànybody in class 10?
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solve plz using log
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Answer 1

Answer:

Step-by-step explanation:

2^x = 3^y = 6^-z

Let 2^x = 3^y = 6^(-z) = k

(1)

2^x = k

Apply log on both sides.

log(2^x) = log k

=> x log 2 = k

=> x = k/log 2

=> (1/x) = (log 2/k)

(2)

3^y = k

Apply log on both sides.

=> log(3^y) = log k

=> (1/y) = (log 3/k)

(3)

6^(-z) = k

Apply log on both sides.

=> log(6^-z) = log k

=> (1/z) = (-log 6/k)

Then,

(1/x) + (1/y) + (1/z)

=> (log 2/k) + (log 3/k) - (log 6/k)

=> 0

Therefore, the answer is Option(A)

#BeBrainly

Answer 2

Step-by-step explanation:

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