ANYBODY IS HERE TO GIVE ME THE DERIVATION OF 1,V=U+AT
Answers
Answered by
1
We know that,
Acceleration = change in velocity/Time taken
Now,
=> Acceleration = Final velocity(v) -Initial velocity(u) / time(t)
=> a = v-u /t
=>at = v-u
or v = u + at
Hence Derived.
Hope it helps :)
Acceleration = change in velocity/Time taken
Now,
=> Acceleration = Final velocity(v) -Initial velocity(u) / time(t)
=> a = v-u /t
=>at = v-u
or v = u + at
Hence Derived.
Hope it helps :)
ALIAKBAR007:
THANKSS A LOT. DEAR FRIEND
Answered by
1
Hii ...
Consider a body having initial velocity u , if it is subjected to an Acceleration " a " so that after time ' t ' its velocity become ' v ' ...
Now, by the definition of acceleration ,
=> accn. = change in velocity/time taken
i.e. a = ( v - u ) / t
=> at = v - u
=> v = u + at
___________________
hope this helps !
Consider a body having initial velocity u , if it is subjected to an Acceleration " a " so that after time ' t ' its velocity become ' v ' ...
Now, by the definition of acceleration ,
=> accn. = change in velocity/time taken
i.e. a = ( v - u ) / t
=> at = v - u
=> v = u + at
___________________
hope this helps !
Similar questions