anybody please answer is Maths question
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So the correct answer is 28cm^2.
Hope it helps.
Hope it helps.
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roneet004:
it is wronh
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HEY MATE HERE IS UR ANSWER
✨✨✨✨✨✨✨✨✨✨✨✨✨✨✨✨✨✨✨✨✨✨✨✨✨✨✨✨
Area of segment bxc= Area of sector - area of triangle.
Since ab and ac are radius
Therefore, Angle ABC = ANGLE ACB (Angles opp. to equal sides are equal)
Angle ACB=45°
Now,Angle ABC+Angle ACB+ Angle BAC=180°{Angle sum property}
Therefore, Angle BAC=90°
Now, Area of sector=theta/360×πr²
=> 90/360*22/7*(7√2)²
=>22/28*98
=>77cm²
Now, areaof TRIANGLE=1/2 *B*H
=>1/2*7√2*7√2
=>1/2*98
=>49cm²
NOW, area of SEGMENT=Area of sector-Area of triangle
=>77-49
=>28cm²
AREA OF SEGMENT BXC=28CM²
HOPE YOU UNDERSTOOD IT
PLZZZZ CHOOSE IT AS BRAINLIEST
I HAD WRITTEN VERY MUCH
PLZZZZZ BROO
✨✨✨✨✨✨✨✨✨✨✨✨✨✨✨✨✨✨✨✨✨✨✨✨✨✨✨✨
Area of segment bxc= Area of sector - area of triangle.
Since ab and ac are radius
Therefore, Angle ABC = ANGLE ACB (Angles opp. to equal sides are equal)
Angle ACB=45°
Now,Angle ABC+Angle ACB+ Angle BAC=180°{Angle sum property}
Therefore, Angle BAC=90°
Now, Area of sector=theta/360×πr²
=> 90/360*22/7*(7√2)²
=>22/28*98
=>77cm²
Now, areaof TRIANGLE=1/2 *B*H
=>1/2*7√2*7√2
=>1/2*98
=>49cm²
NOW, area of SEGMENT=Area of sector-Area of triangle
=>77-49
=>28cm²
AREA OF SEGMENT BXC=28CM²
HOPE YOU UNDERSTOOD IT
PLZZZZ CHOOSE IT AS BRAINLIEST
I HAD WRITTEN VERY MUCH
PLZZZZZ BROO
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