Math, asked by BrainlyHelper, 1 year ago

If A + B = 90° and cos B=\frac{3}{5}, what is the value of sin A?

Answers

Answered by nikitasingh79
10

SOLUTION :  

Given : cos B = 3/5 , A + B = 90°  

A + B = 90°  

A = 90° - B  

On putting sin on both sides,  

sin A = sin(90° - B )

sin A = cos B

[ sin (90° -θ ) = cos θ )]

sin A = 3/5

[cos B = 3/5]

Hence, the value of sin A  is 3/5 .

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Answered by Rememberful
23
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