anybody please give me answer
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For any regular polygon, the magnitude of an interior angle is (n-2)*180 deg/n, where n is the number of sides. For a regular Pentagon,
internal angle is (5-2)*180 deg/5.
which is 108 deg.
For conversion of degrees into radians multiply by 'pi' and divide by 180 deg.
So, 108° = 3π/5.
Similarly for Hexagon and Octagon substitute 'n' as 6 and 8 in
(n-2)*180 deg/n.
Hope this helps you out.
internal angle is (5-2)*180 deg/5.
which is 108 deg.
For conversion of degrees into radians multiply by 'pi' and divide by 180 deg.
So, 108° = 3π/5.
Similarly for Hexagon and Octagon substitute 'n' as 6 and 8 in
(n-2)*180 deg/n.
Hope this helps you out.
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