Question

anybody please help me it's urgent....
physics...​

Answer 1

Explanation:

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Answer 2

Physical Quantities having the following units are as follows:

• Kelvin : Temperature

• Candela : Luminous Intensity

Advantages of SI unit :

• It makes the measuring system common (same) in different regions and countries , more universal.

• Makes the measuring system more accurate.

Dimensions of :

$1) \: \: \sf{linear \: momentum = ML{T}^{ - 1} }$

$2) \: \: \sf{power = M{L}^{2} {T}^{ - 3} }$

Checking the Correct dimensions:

LHS:

$\sf{mv = \bigg \{M \times L{T}^{ - 1} \bigg \}}$

$= > \sf{mv = \bigg \{M L{T}^{ - 1} \bigg \}}$

RHS:

$\sf{F \times t = \bigg \{ML{T}^{ - 2} \times T\bigg \}}$

$= > \sf{F \times t = \bigg \{ML{T}^{ - 1} \bigg \}}$

So, LHS = RHS.

Dimensions of a and b :

$\boxed{ \sf{ \bigg \{a \bigg \} = \bigg \{x \bigg \} = \bigg \{L \bigg \}}}$

$\sf{ \bigg \{b {t}^{2} \bigg \} = \bigg \{x \bigg \} = \bigg \{L \bigg \}}$

$= > \sf{ \bigg \{b {T}^{2} \bigg \} = \bigg \{L \bigg \}}$

$\boxed{ = > \sf{ \bigg \{b \bigg \} = \bigg \{L{T}^{ - 2} \bigg \}}}$

HOPE IT HELPS.