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i have a doubt : how did AN and AM became equal?
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Hey there !!
Consider the triangle ABC
It is given that -
Angle N = Angle B ( each 90°)
Proof -
Now in ∆ABM and in ∆ ACN
/_ N = /_ M ( given)
/_A = /_ A ( common)
BM = NC ( since /_ N = /_ M)
∆AMB =~ ∆ ANC ( SAS)
Now we have. by Criterion of similarity ,
∆ABC _~ ∆ACB ...1)
AB = AC
2 AN = 2AM .......2)
For further information please see on attached image
Hope this helps u!!
Consider the triangle ABC
It is given that -
Angle N = Angle B ( each 90°)
Proof -
Now in ∆ABM and in ∆ ACN
/_ N = /_ M ( given)
/_A = /_ A ( common)
BM = NC ( since /_ N = /_ M)
∆AMB =~ ∆ ANC ( SAS)
Now we have. by Criterion of similarity ,
∆ABC _~ ∆ACB ...1)
AB = AC
2 AN = 2AM .......2)
For further information please see on attached image
Hope this helps u!!
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