anyone can aolve then.....
Attachments:

Answers
Answered by
6
tanA =sinA/cosA
A.T.Q.
tan4A=sin4A/sin5A
sin5A=sin4A/tan4A
sin5A=cos4A
cos(90-5A)=cos4A
90-5A=4A
90=9A
A=10
A.T.Q.
tan4A=sin4A/sin5A
sin5A=sin4A/tan4A
sin5A=cos4A
cos(90-5A)=cos4A
90-5A=4A
90=9A
A=10
Similar questions