anyone can do this????? 6th sum.
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aloha!
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7th question:
we know that both the wall and the bricks are cuboids and the volume of cuboid is lbh
now, for the wall the volume would be 1000 × 400 × 24 cm²
and the volume of one brick is = 24 × 12 × 8 cm²
{ note: 1.5 is written by mistake over there }
now,
n × 24 × 12 × 8 = 1000 × 400 × 24 { n = number of bricks }
n =
[tex] \frac{1000 X 400 X 24 }{24 X 12 X 8} [/tex]
n= 4166 bricks { approx. }
»»————- ★ ————-««
hope it helps :)
»»————- ★ ————-««
6th question:
we are given the circumference = 17.6
2 r = 17.6
r = 2.8 m
r = 280 cm
and the curved surface area of dome= 2 r²
= 2 × 22/7 × 280 × 280
= 492800 cm²
cost of painting 100 cm² = rs 5
1 cm² = 5/100
492800 cm² = 5/100 × 492800
= rs 24640
»»————- ★ ————-««
hope it helps :)
»»————- ★ ————-««
7th question:
we know that both the wall and the bricks are cuboids and the volume of cuboid is lbh
now, for the wall the volume would be 1000 × 400 × 24 cm²
and the volume of one brick is = 24 × 12 × 8 cm²
{ note: 1.5 is written by mistake over there }
now,
n × 24 × 12 × 8 = 1000 × 400 × 24 { n = number of bricks }
n =
[tex] \frac{1000 X 400 X 24 }{24 X 12 X 8} [/tex]
n= 4166 bricks { approx. }
»»————- ★ ————-««
hope it helps :)
»»————- ★ ————-««
6th question:
we are given the circumference = 17.6
2 r = 17.6
r = 2.8 m
r = 280 cm
and the curved surface area of dome= 2 r²
= 2 × 22/7 × 280 × 280
= 492800 cm²
cost of painting 100 cm² = rs 5
1 cm² = 5/100
492800 cm² = 5/100 × 492800
= rs 24640
»»————- ★ ————-««
hope it helps :)
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