Question

anyone give answer??

Answer 1

We have
(a³+b³+c³-3abc) = (a+b+c) (a²+b²+c²-ab-bc-ca)
= (a+b+c) (a+b+c) ²-3(ab+bc+ca)
=5*(5²-3*10)
=5*(25-30)
=5*(-5)=-25
Hence, (a³+b³+c³-3abc)=-25