Question

anyone help me to solve this question

Answer 1

Let the common ratio be x

Given that altitude of the field = 6x.

Given that base of the field = 5x.

Given that cost of field per hectare = 36720.

Given Total cost = 4957200.

Area = 4957200/36720

         = 135 hectares

         = 1350000 sq.m


We know that Area of triange = 1/2 * b * h

1/2 * 6x * 5x = 1350000

30x^2/2 = 1350000

15x^2 = 1350000

x^2 = 90000

x = 300m.


Therefore, The altitude of the field = 6 * 300

                                                           = 1800


Therefore, the base of the field = 5 * 300

                                                      = 1500.


By Pythagoras theorem, We know that

AC^2 = AB^2 + BC^2

AC^2 = (1500)^2 + (1800)^2

AC^2 = 2250000 + 3240000

AC^2 = 5490000

$AC = \sqrt{5490000}$

AC = 2343.07m.



Therefore the altitude = 1800m, base = 1500m, Hypotenuse = 2343.07m.


Hope this helps!