Question

Anyone in class 12th can help to solve this inverse trigonometry question? (in attachment)​

Answer 1

Step-by-step explanation:

4cos⁻¹(x)+sin⁻¹x=π

WKT

cos⁻¹(x)+sin⁻¹x=π/2

3cos⁻¹x+π/2=π

⇒3cos⁻¹x=π/2

⇒cos⁻¹x=π/6

we know that

cos⁻¹√3/2=π/6

⇒x=√3/2