Question

Anyone know tis confusing question???

Answer 1

BD =DC. ( given)
therefore, angle DBC =angle DCB
therefore, angle DBC = angle DCB =30
now,

in triangle bdc
angle B + angle D + angle C = 180
angle D = 180 - 60 = 120

now,
angle D + angle A = 180
angle A = 180 - 120 = 60

now, angle O =2angle A
angle O = 2* 60 = 120

Answer 2

find out,angle BAC and angle BOC
given, BD = DC
solution, in triangle BCD.
angle CBD= angle BCD
so, angle BCD=30
angle BCD+angle BDC +angle DBC =180(L.P.)
3o+angle BDC +30=180
60+angle BDC=180
angle BDC=180-60
angle BDC=120
angle BOC =120
angleBAC=1/2angleBOC
angleBAC=60