Question

Anyone out there who can solve this? [From-E.M.I. and A.C.]

Answer 1

Va - Vb : 0

=>Potential difference bw O and A is 1/2 BwR^2

=>Potential difference bw O and B is 1/2 BwR^2

Answer 2

Answer:

Suppose the length of the rod is greater than the radius of the circle and rod rotates anticlockwise and suppose the direction of electrons in the rod at any instant be along +y direction .

Suppose the direction of the magnetic field is along +z direction.

Then, using Lorentz law, we get the following

Thus, the direction of force on the electrons is along -x axis.

So, the electrons will move towards the centre i.e the fixed end of the rod. This movement of electron will effect in current and thus it will generate an emf in the rod between the fixed end and the point touching the ring.

Let 0 be the angle between the rod