anyone please answer it please
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Let u, v & w be the initial, at the end of 2s & at the end of 6 s respectively.
Using average velocity *time = distance
(u + v )*2/2 = 200 we get u+ v = 200 m/s
Similarly, v + w =2 *220/4 = 110 m/s
Acceleration = ( w-u)/ time = ( 110 - 200)/ (4+2) = -15 m/s^2
We have u+ v = 200 m/s => 2u + at = 2u - 30 => u = 115 m/s.
Velocity at the end of 7 s is u + 7a = 115 - 105 = 10 m/s.
Using average velocity *time = distance
(u + v )*2/2 = 200 we get u+ v = 200 m/s
Similarly, v + w =2 *220/4 = 110 m/s
Acceleration = ( w-u)/ time = ( 110 - 200)/ (4+2) = -15 m/s^2
We have u+ v = 200 m/s => 2u + at = 2u - 30 => u = 115 m/s.
Velocity at the end of 7 s is u + 7a = 115 - 105 = 10 m/s.
NANDANI1234raj:
sorry but the answer is wrong
your process is correct thanks for your help but I think you should look at the question carefully it is not 6 sec it's 5 sec
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hope it helps you. . Answer is wrong as well as question is incomplete in book
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