anyone please answer this fast
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vivo1726:
is (x²-3) <- have bracket
< not <-
< -
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Answered by
0
(5x²-15+2√6x²-6√6)+(5x²-15-2√6x²+6√6)
= 10x²-30= 10
= 10x² = 40
= x² = 40/10
= x² = 4
=x =+√4
=x = + 2.......
we get -15 and -15 = -30
ya, root 1.6
how
i cannot explain it like dis , well look i think bracket with red pen is not there in the question
so , 10xsquare -6=10 ,as irrational terms will be cancel ,solve it then you will get root 1.6
why u take it equal to 0
It is given that it is equal to 10
yea yea thanks I got the answer
which is right??
root 1.6 is right one
Answered by
0
HERE IS YOUR ANSWER ⤵
Now by taking x²-3 as common....
x²-3 (5+2√6)+(5-2√6)=10
x²-3 {5+ 2√6+5- 2√6} =10
x²-3 {10} = 10
10x² -30 = 10
10x² = 10 +30
x² = 40/10
x = √4
x =±2
HOPE THIS HELPS U......❤
If it helps u then plzz mark it as BRAINLIEST
❤❤ THANK YOU ❤❤
Now by taking x²-3 as common....
x²-3 (5+2√6)+(5-2√6)=10
x²-3 {5+ 2√6+5- 2√6} =10
x²-3 {10} = 10
10x² -30 = 10
10x² = 10 +30
x² = 40/10
x = √4
x =±2
HOPE THIS HELPS U......❤
If it helps u then plzz mark it as BRAINLIEST
❤❤ THANK YOU ❤❤
atleast thank uss
I had done a lot of hardwork for that
and also mark my answer brainliest
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