Question

P(x) =63x^2-7x+9 find the sum and product

Answer 1

Hello!

p(x) = 63x² - 7x + 9

$\textbf{Here}$,

• $\sf a = \sf 63$
• $\sf b = \sf - 7$
• $\sf c\: = \sf \:\: 9$

$\underline{\sf Then}$ :

♦ Sum of Zeroes = $- \dfrac{\sf b}{\sf a}$ = $\dfrac{\sf 7}{\sf 63}$ = $\boxed{ \dfrac{\sf 1}{\sf 9}}$

♦ Product of Zeroes = $\dfrac{\sf c}{\sf a}$ = $\dfrac{\sf 9}{\sf 63}$ = $\boxed{\dfrac{\sf 1}{\sf 7}}$



Cheers!

Answer 2

63x^2 - 7x + 9

here a = 63 ,b = -7 ,c = 9

sum of zeros = - b /a

= -(-7) / 63 = 7 / 63

= 1 /9

product of zeros= c / a

= 9 /63 = 1 /7

hope it helps !
thank you !