Question

anyone please answer this
if anyone do this correctly i will give them 10 thanks​

Answer 1

Answer:

Here's the answer of your question,grab it.

Explanation:

Given-

side of the Pentagon=6cm

Target-

find the area and draw a triangle with the same area.

Area of Pentagon-

$(perimeter \times apothem) \div 2$

the shape is regular Pentagon so the apothem must be equal to side-

so apothem=6cm

perimeter-

$5a$

so-

$5 \times 6 = 30 \: cm$

now we have perimeter,let's use it in the formula-

$\frac{30 \times 6}{2}$

$= 90 \: {cm}^{2}$

so we have found the area of Pentagon and it must be equal to the triangle's area .

we can make a right angle∆ with the same area as-

$\frac{1}{2} \times b \times p$

$\frac{1}{2} \times b \times p = 90$

$90 \times 2 = b \times p$

so we can take the dimensions as-

$base = 9</u></em></strong><strong><em><u>0</u></em></strong><strong><em><u>cm$

$perpendicular = 2 \: cm$

$hypotenus \: = 9 </u></em></strong><strong><em><u>2</u></em></strong><strong><em><u>\: cm$

I will make a rough diagram for your help.

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