Question

The position x of a particle moving in a straight line
varies with time t as x = 6 + 12t - 2t^2? (where x is
in metre and t is in second). The distance travelled
by the particle in first three seconds is​

Answer 1

Answer:we know that

V=ds÷dt

V=d(6+12t-2t^2)/St

V=0+12-2*2t

=12-4t

Now we know that

Velocity=distance/time

Distance=velocity*time

=(12-4t)t

Puting value of time

=12-4*3*3

=12-36

=-24

Distance can not be negative so distance traveled in 3s is 24 m

Explanation:

Answer 2

Answer:

Distance, x = 24 meters

Explanation:

Given that,

The position of a particle is given by :

$x=6+12t-2t^2$.... (1)

We need to find the distance travelled by the particle in first three seconds.

Put the value of t = 3 s in equation (1) as :

$x=6+12(3)-2(3)^2$

x = 24 meters

So, the distance travelled by the particle is 24 meters. Hence, this is the required solution.