Question

anyone please help me to solve this question​

Answer 1

Answer:

a) x²/16 + y²/4 = 1

b) x² + y² - 2ky + k² - r² = 0

c) x² + y² - 6y - 16 = 0

Step-by-step explanation:

Solution----->

1) Plzzz see the attachment

2)

a) We know that,

Coordinates of foci of ellipse = ( ± ae , 0 )

Vertices of ellipse = ( ± a , 0 )

Eccentricity of ellipse = √{ 1 - ( b² / a² ) }

Equation of ellipse

x²/a² + y²/b² = 1

b) If , coordinates of centre = ( h , k )

Radius of circle = r

Equation of circle is ,

( x - h )² + ( y - k )² = r²

c) General equation of circle is

x² + y² + 2gx + 2fy + c = 0