Anyone please send me the solution of this above question
Today I am going to appear my PT2 math exam.
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(x-2)^2+ 4
=x^2+4-4x+4
=x^2-4x+8
X=-b ±root over b^2-4ac/2a
X=4±root over 16-4*1*8/2*1
X=4±root over 16-32/2
X=4±root over - 16/2
X=4±root over 16i/2
X=4±4i/2
X=2(2±2i)/2
X=2±2i
=x^2+4-4x+4
=x^2-4x+8
X=-b ±root over b^2-4ac/2a
X=4±root over 16-4*1*8/2*1
X=4±root over 16-32/2
X=4±root over - 16/2
X=4±root over 16i/2
X=4±4i/2
X=2(2±2i)/2
X=2±2i
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