Question

anyone please solve this problem ​

Answer 1

Given :

• $a ( y + z ) = b ( z + x ) = c ( x + y )$

To Show :

• $( \frac{y - z}{a ( b - c )}) = ( \frac{z - x}{b ( c - a )}) =( \frac{x - y}{c ( a - b )})$

Assuming ,

⟶ $n = a ( y + z ) = b ( z + x ) = c ( x + y )$

⟶ $n = a ( y + z ) , n = b ( z + x ) , n = c ( x + y )$

➳ $y + z = ( \frac{n}{a})$ ...... [ 1 st ]

➳ $z + x = ( \frac{n}{b})$...... [ 2 nd ]

➳ $x + y = ( \frac{n}{c})$ ...... [ 3 rd ]

Subtracting ( 2 - 1 ) , ( 3 - 2 ) , ( 1 - 3 ) , We get :

➳ $x - y$ = $\frac{n ( a - b )}{ab} ...... [ 4th ]$

➳ $y - z$ = $\frac{n ( b - c )}{bc}...... [ 5 th ]$

➳ $z - x$ = $\frac{n ( c - a )}{ac}...... [ 6 th ]$

⟹ $\frac{x - y}{c ( a - b )} = ( \frac{n ( a - b ) / ab}{c ( a - b )}) = ( \frac{n}{abc})$

⟹ $\frac{y - z}{a ( b - c )} = ( \frac{n ( b - c ) / bc}{a ( b - c )}) = ( \frac{n}{abc})$

⟹ $\frac{z - x}{b ( c - a )} = ( \frac{n ( c - a ) / ac}{b ( c - a )}) = ( \frac{n}{abc})$

⟹ $\bold{( \frac{y - z}{a ( b - c )}) = ( \frac{z - x}{b ( c - a )}) =( \frac{x - y}{c ( a - b )})}$

So, It's Done !!

Answer 2

Answer:

are u ok? or what happens? siso? thank you for your answer that you have given it was the correct one . be happy