Question

anyone pls solve this

Answer 1

∆ᴩᴛꜱ~∆ᴩʀq. (ʙy ᴀᴀ ꜱɪᴍɪʟᴀʀɪᴛy)

Answer 2

Answer:

Step-by-step explanation

∠1=∠2  SO PT=PS............................1ST EQUATION

ΔNSQ≅ΔMTR

SO ∠NQS =∠MRT

∠PQR =∠PRT

PR=PQ    ........................  2ND EQUATION

FROM 1ST AND 2ND

PT÷PR = PS ÷PQ

ALSO ∠TPQ =∠RPQ .........[COMMON]

ΔPTS  IS SMILAR  TOΔPRQ