anyone plsz solve 22 q no.
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Answer:(d)0.01 is the right one
smrutisubudhicreatea:
thanks for the trial though
I'm sorry !! The correct one is (b)0.0075
yeah
can u post the process if u don't mind
Ask this one again so that I'll give you the pic of solution!!!!! Or delete my previous answer
Given 250 ml of 0.1M K I => 0.025 moles
and 250 ml of 0.02M of KMnO₄ => 0.005 moles
I am not sure of the reaction that takes place.... We need to find the products and then balance equation first.
2 K Mn O₄ + 6 K I => 2 Mn O₂ + 3 I₂ + 4 K₂ O
So n moles of Potassium Permanganate reacts with 3 n moles of potassium iodide to produce 1.5 n moles of Iodine gas.
So 0.005 moles of permanganate will react with 0.015 moles of Iodide, and produce 0.0075 moles of Iodine gas.
and 250 ml of 0.02M of KMnO₄ => 0.005 moles
I am not sure of the reaction that takes place.... We need to find the products and then balance equation first.
2 K Mn O₄ + 6 K I => 2 Mn O₂ + 3 I₂ + 4 K₂ O
So n moles of Potassium Permanganate reacts with 3 n moles of potassium iodide to produce 1.5 n moles of Iodine gas.
So 0.005 moles of permanganate will react with 0.015 moles of Iodide, and produce 0.0075 moles of Iodine gas.
keep asking
oh thanks ,
had a little idea
yessss!
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