Question

Anyone provide great answerr . ​

Answer 1

SOLUTION :-

=> (I) The probability of getting a red marble = no. of red marbles / total number of marbles.

=>5/(5+8+4)

=>5/17.

=>(II) The probability of getting a white marble = no. of white marble / total number of marbles.

=>8/(5+8+4)

=>8/17.

=>(III)The probability of getting a green marble = no. of green marble / total number of marbles.

=>4/(5+8+4)

=>4/17.

Now,

=> P(a green marble)+P(not a green marble) = 1

=>P(not a green marble) = 1- p(a green marble)

=> 1-4/17

=> 17 - 4/17

=> .°. 13/17.

Thus, the probability of not getting a green marble is 13/17.

Answer 2

Given

$\bold{Total \ no : \ of \ red \ marbles} = 5\\\bold{Total \ no : \ of \ white \ marbles} = 8\\\bold{Total \ no : \ of \ green \ marbles} = 4\\\\\\=> \bold{Total \ no: \ of \ marbles} = 5+8+4 = 17 \ marbles$

$i) \bold{Probability \ getting \ a \ red \ marble} =\boxed{\boxed{\bold {\frac{5}{17} }}}$

$ii) \bold{ Probabability \ of \ getting \ a \ white \ marble} =\boxed{ \boxed{\bold{\frac{8}{17} }}}$

$iii) \bold{ Probability \ of \ getting \ green} = \frac{4}{17} \\=> \bold { Probability \ of \ not \ getting \ green} =1- \frac{4}{17}$

                                                                $=\boxed{ \boxed{\bold{\frac{13}{17} }}}$