Question

plss help in the figure given

Answer 1

area of trapezium=1/2×{sum of parralel lines)× height=

=1/2×(28+40)×9=306cm^2

thanks for asking

Answer 2

AREA OF TRAPEZIUM = AREA OF RECTANGLE + AREA OF TRIANGLE

AREA OF RECTANGLE = lb = 9*28 = 252 cm²

area of triangle = 1/2 bh = 9 * 12 /2 = 9*6 = 54 cm²

area of trapezium = 252 + 54 = 306 cm²