anyone quick solve the problem
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(i)AD=DP
APD=PAD....angle opposite to equal sides..1
now AB||CD,AP is the transversal.
•APD=BAP....alternate angles are equal....2
from 1 and 2,
So,PAD=BAP.
hence AP bisects Angle A.
APD=PAD....angle opposite to equal sides..1
now AB||CD,AP is the transversal.
•APD=BAP....alternate angles are equal....2
from 1 and 2,
So,PAD=BAP.
hence AP bisects Angle A.
myselfyiri:
second and third parts?
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