Question

Anyone tell this answer step by step ....
The answer should be 3/7...
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Answer 1

Answer:

Let x and y be the numerator and denominator of the required fraction...

Given that...

x = y - 4 AND

$\frac{x - 1}{y + 3} = \frac{1}{5}$

SUBSTITUTING THE VALUE OF x

$\frac{y - 4 - 1}{y + 3} = \frac{1}{5} \\ 5(y - 5) = 1(y + 3) \\ 5y - 25 = y + 3 \\ 4y = 28 \\ y = 7$

THEN

$x = y - 4 \\ = 7 - 4 \\ x = 3$

THE REQUIRED FRACTION IS X/Y = 3/7

Answer 2

Step-by-step explanation:

Let the Denominator be 'x'

the original numerator  = x - 4

Then, the original fraction = x-4 / x

Now, 1 is added to the numerator so new numerator = x - 4 - 1

                                                                                        = x - 5

3 is added to the denominator so new denominator = x + 3

Then, the new fraction = x - 5 / x + 3

A/Q

x - 5 / x + 3 = 1/5

5(x - 5)  =  1(x + 3)

5x - 25 = x + 3

5x - x = 3 +25

4x = 28

x = 7

So, the orginal denominator is 7

Orginal fraction = x - 4/ x

                          = 7 - 4 / 7

                          = 3/7