Question

Anyone who knows the answer, please help:)
Explain the answer as well.
No spams!!​

Answer 1

For our bad luck, the inclination of the slope is not given! Ah, let me call it θ, with the horizontal.

And, what to tell, assume the wedge surface to be frictionless!

Well, these will be in vain finally! But we have to have them.

Since the block is released from rest at A, u = 0.

The acceleration acting on the block is, a = g sinθ.

Let the displacement of the block, i.e., the length of the slanted surface of the wedge, be s. Then,

s sinθ = h

s = h / sinθ

Then, final velocity at B, by the third kinematic equation, will be given as,

v² = u² + 2as

v² = 0² + 2 g sinθ h / sinθ

v = √2gh

This is the velocity of the block at B.