AP. (1, x), (5, 2),(9,5) are collinear then find the value of x
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I'm sorry! Please make tge last step right! Yeah your ans is -1
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1/2(1/x*5/2*9/5*1/x)=0
1/2[(2+25+9x)-(5x+18+5)]
1/2(27+9x-5x-23)
1/2(4+4x)=0
4+4x=0
4x=-4
x=-4/4
x=-1
I think so this will be correct
1/2[(2+25+9x)-(5x+18+5)]
1/2(27+9x-5x-23)
1/2(4+4x)=0
4+4x=0
4x=-4
x=-4/4
x=-1
I think so this will be correct
which class
10th
o same here
hmm nc
ok
then
what your aim
doctor urs
IAS officer
hmm
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