AP is an=3+4n find the sum of first fifteen terms
Answers
Answered by
62
a1=3+4(1)=7
a15=3+4(15)=63
n=15
S15=n(a1+a15)/2
=15(7+63)/2
=15(70)/2=15(35)
=525
a15=3+4(15)=63
n=15
S15=n(a1+a15)/2
=15(7+63)/2
=15(70)/2=15(35)
=525
Answered by
25
hope this helps you
Attachments:
Similar questions
Computer Science,
7 months ago
English,
7 months ago
English,
7 months ago
Math,
1 year ago
Business Studies,
1 year ago
Science,
1 year ago
Math,
1 year ago