APB is a tangent to each circle centre O.
Find x.
Thanks in advance
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if the line which subtends the angle 58 is the diameter i can dolve the whole question very easily
It is the diameter
kkk then
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Let The Diameter naming Is C nd D
Now,
∠CPD = 90° [angle subtended by the diameter = 90°]
In ΔCPD
∠CPD + ∠PDC +∠DCP = 180° [angle sum property]
90 + 58 + ∠DCP = 180
∠DCP = 180 - 148
∠DCP = 32°
Now,
∠DCP = ∠APD [Alternate Segment]
∠APD = 32°
Now,
∠APD + ∠CPD + ∠DPB = 180°
32 + 90 + x = 180
x = 180 - 122
x = 58°
I hope U Understood If U r Satisfied Only then mark it As Brainliest
THANKX
Now,
∠CPD = 90° [angle subtended by the diameter = 90°]
In ΔCPD
∠CPD + ∠PDC +∠DCP = 180° [angle sum property]
90 + 58 + ∠DCP = 180
∠DCP = 180 - 148
∠DCP = 32°
Now,
∠DCP = ∠APD [Alternate Segment]
∠APD = 32°
Now,
∠APD + ∠CPD + ∠DPB = 180°
32 + 90 + x = 180
x = 180 - 122
x = 58°
I hope U Understood If U r Satisfied Only then mark it As Brainliest
THANKX
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