Apne ka design the shape of rhombus whose sides are 13 cm each and one of the diagonal is 24 cm find the cost of painting both the sides of the play card @ rupees 5.50 per CM square
Answers
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The diagonal of rhombus bisect each other and form at right angle!!!
Let, ABCD is a rhombus with diagonal AC and BD
which intersect at point O
Ac=10cm OA=1/2.10cm
OA=1/2.10=5cm
OA=5cm
AB=13cm
in AOB, by Pythagoras theorem!!!!! ❤
ABsq. =OBsq. +OAsq.
13sq. =OBsq. +5sq.
=169=OBsq.+25
OB=169-25
⏮️OBsq. =144
OB =12cm
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Answer:
The diagonals of rhombus bisect each other at right angle.
Let ABCD is a rhombus with diagonals AC and BD which intersect each other at O.
AC = 10 cm , OA =1/2×AC=
OA= (½) × 10= 5 cm
OA= 5 cm
AB = 13 cm (given)
In ∆ AOB
By Pythagorean theorem
AB²= 0B²+ OA²
13² = OB² + 5²
169 = OB² + 25
OB²= 169 – 25
OB² =144
OB= √144
OB= 12 cm
Diagonal BD = 2 x 12= 24 cm
Hence, the length of other Diagonal = 24 cm
HOPE THIS WILL HELP YOU....