Question

Centre of the circle aise do answer jaise OA,OB,OC​

Answer 1

Answer:

Diagram kha hai????????

Answer 2

Step-by-step explanation:

Since ∠OAC=∠OBC=90

∘

and ∠AOB=120

∘

∴∠ACB=60

∘

Also ∠CAB=90

∘

−∠OAM=60

∘

and ∠CBA=90

∘

−∠OBM=60

∘

Hence \Delta ABC is equilateral

CA=CB=AB=2AM=

3

r

Then CM = CA cos 30

3

r.

2

3

=

2

3

r

Further OM=OAcos60

∘

=

2

r

∴OM=OD−OM=r−

2

r

=

2

r

and CD=CM−DM=

2

3

r−

2

1

r=r

∴ OD:DC=r:r:1:1

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