Question

app particles moving along a straight line with a constant acceleration of -4 metre per second square passes through a point a on the line with a velocity of 20​

Answer 1

Explanation:

uy=10sin60=53√m/s

⇒t=2uyg=2×53√10=3√s

Sx=uxt+12axt

2

1.15=5×t−12a×t

2

1.15=5×3√−32a

3a

2

=5×1.73−1.15=8.65−1.15

3a

2

=7.5

⇒a=153=5m/s

2