Question

Apparatus that liquefies helium is in a laboratory at 296 K. The helium in the apparatus is at 4.0 K. If 150 mJ of heat is transferred from the helium, find the minimum amount of heat delivered to the laboratory.

Answer 1

Answer:

Solution:-

To obtain the minimum amount of heat delivered to the laboratory, substitute 150 mJ for QL, 296 K for TH and 4.0 K for TL in the equation QH = QL (TH/ TL),

QH = QL (TH/ TL)

     = {(150 mJ). (10^-3 J/1 mJ)} (296 K/4.0 K)

     = 11 J

From the above observation we conclude that, the minimum amount of heat delivered to the laboratory would be 11 J.

Answer 2

Explanation:

thanks for free points  give more points