Question

Application : 7. Ifit requires 173.25 sq cm of sheet to make a hemisphercal bowl then let us
write by calculating the length of diameter of forepart of the bowl.​

Answer 1

Answer:

Area of hemispherical bowl = 2pi.r^2 where r is the radius of the bowl

2.pi.r^2 = 173.25

2r^2 = 173.25/pi

2×2r^2=2×173.25/pi

(2r)^2=2×173.25×7/22=110.25

2r=√110.25=10.5

2r = diameter = 10.5 cm Ans

Answer 2

Given :- if it requires 173.25 sqcm of sheet is required to make a hemispherical bowl. Let us write by calculating the length of diameter of the forepart of the bowl. ?

Solution :-

we know that,

• curved surface area of a hemispherical bowl is = 2 * π * (radius)² .
• Diameter = 2 * radius .
• Sheet total area = curved surface area of a hemispherical bowl .

Let us assume that, radius of hemisphere is r cm.

so, comparing area , we get,

→ 2 * π * (r)² = 173.25

→ 2 * (22/7) * (r)² = (17325/100)

→ (r)² = (17325 * 7) / (44 * 100)

→ (r)² = (1575 * 7)/400

→ (r)² = (11025/400)

→ (r)² = (105/20)²

square root both sides,

→ r = (105/20) cm.

→ r = 5.25 cm.

therefore,

→ Diameter of hemispherical bowl = 2 * 5.25 = 10.5 cm. (Ans.)

Hence, the diameter of the forepart of the bowl is 10.5 cm.

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