Question

application
Point
of
F = 5i-3j+ 2k is
moved from
point
P(2,7, 2) to point Q(-5,2,3)
What
is work done
by force
​

Answer 1

Answer:

Explanation:

work done by force=∫F.ds

F=5i-3j+2k

displacement=(final position vector)-(initial position vector)

                      =(-5i+2j+3k)-(2i+7j+2k)

                       =(-7i-5j+1k)

work=(5i-3j+2k).(-7i-5j+1k)

      = -35+15+2=-18Joules