Question

Applied Ohm's law to obtain the relation for the combined resistance when three resistors R1 R2 and R3 are connected in parallel

Answer 1

Answer:

hey mate here is ur ans

acc. to ohm law

V = IR

three resistance connected in parrellel

1/R = 1/R1+1/R2+1/R3

R = R1. R2. R3/R1+R2+R3

V= I[R1.R2.R3/R1+R2+R3]

HOPE IT HELP U

Answer 2

Answer :

Let us consider three resistors R1, R2 and R3 connected in parallel.

Diagram in the attachment.

In a parallel connection of resistors, the current flowing through to all the three resistors will be different.

Let us assume the current flowing through Resistor 1 is I 1, the current flowing through Resistor to is I 2 and the current flowing through Resistor 3 is I 3.

So, total current in the circuit is : I = I 1 + I 2 + I 3. ---- (1)

The potential difference through all the three resistors is same.

By Ohm's law [At constant temperature and pressure, potential difference in the circuit is directly proportional to the current flowing through it] :

➸ I = V/R

➸ I 1 = V/R1

➸ I 2 = V/R2

➸ I 3 = V/R3

Now, substituting the value of I 1, I 2 and I 3 in Equation 1.

⇒ V/R = V/R1 + V/R2 + V/R3

⇒ V/R = V (1/R1 + 1/R2 + 1/R3)

⇒ 1/R = 1/R1 + 1/R2 + 1/R3

Thus, we got the relation for the combined resistance when three resistors R1, R2 and R3 are connected in parallel.