Question

apply identity (2p-q)(2p-q)​

Answer 1

$Given \: (2p-q)(2p-q)$

$= (2p-q)^{2}$

$= (2p)^{2} - 2 \times 2p \times q + q^{2}$

/* By algebraic identity */

$\boxed{\pink{ (a-b)^{2} = a^{2} - 2ab + b^{2} }}$

$Here, a = 2p \:and \: b = q$

$= 4p^{2} - 4pq + q^{2}$

Therefore.,

$\green { (2p-q)(2p-q)}$

$\green { = 4p^{2} - 4pq + q^{2} }$

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