Question

Approximately what mass of CuSO4∙5H2O (Formula Mass = 250 g∙mol-1) is required to prepare 100.0 mL of 0.50M copper (II) sulfate solution?
a) 6.125 b) 12.5 c) 25.0 d) 37.5 e) 250

Answer 1

Answer:

Explanation:i think c is the right one

Answer 2

Molarity ==> Given Mass / Molecular mass x 1000/ volume

0.5 = mass/250 x 1000/100
0.5 = mass/25
0.5 x 25 = 12.5 g //


hope this helps