Approximately what mass of CuSO4∙5H2O (Formula Mass = 250 g∙mol-1) is required to prepare 100.0 mL of 0.50M copper (II) sulfate solution?
a) 6.125 b) 12.5 c) 25.0 d) 37.5 e) 250
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Explanation:i think c is the right one
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Molarity ==> Given Mass / Molecular mass x 1000/ volume
0.5 = mass/250 x 1000/100
0.5 = mass/25
0.5 x 25 = 12.5 g //
hope this helps
0.5 = mass/250 x 1000/100
0.5 = mass/25
0.5 x 25 = 12.5 g //
hope this helps
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