ar ∆ABC, DE || BC. If DE = 3 cm, BC = 6 cm, and ar(A ADE) = 15 cm?, Find the area of ∆ ABC
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DE || BC
DE = 3 cm,
BC = 6 cm area
(∆ADE) = 15 cm2
Now, In ∆ABC
DE ||BC. Therefore triangles, ∆ADE and ∆ABC are similar
Area of traingle ABC=60cm^2
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