Aravind sets up a current, I= 2 A, across a resistor. What is the magnitude of net charge ‘q’, flowing through the resistor in time, t=10 s? q =___ C.
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Answered by
2
Given :
Current = I= 2A
time = t=,10s
net charge = q=?
Formula :
I= Q/t
Q= Ix t
= 2 x 10
Q= 20 Coulombs
∴the magnitude of net charge ‘q’, flowing through the resistor in time, t=10 s is 20 C
Answered by
2
Answer:
- According to the question, Aravind sets up a current, I= 2 A, across a resistor.
- We have to find, What is the magnitude of net charge ‘q’.
- Flowing through the resistor in time, t=10 s? q =___ C.
Know terms:
- Current = 2A
- Time = 10s
Formula:
- Current = Net charge/Time
- Net charge = Current × Time
- 2 × 10 = 20
.•. 20 Coulombs is the answer.
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