Arb represents a semicircular plate wherea ab is 14cm. A semicircle aso is cut away. (o is the midpoint of ab).what is the area of remaining portion
Answers
Answered by
4
area= (πr1^2/2) - (πr2^2/2)
=π\2(r1^2 - r2^2)
=11/7(49-12.25)
=11/7(36.75)
=57.75
=π\2(r1^2 - r2^2)
=11/7(49-12.25)
=11/7(36.75)
=57.75
Similar questions