Math, asked by vikasprj8286, 1 year ago

arc length =s=..........​

Answers

Answered by IamIronMan0
0

Answer:

In circles

2\pi \: r( \frac{ \theta}{2\pi} ) \:  \:  \:  \: or \:  \:  \:  \: r \theta

for more complex functions

let \:  \:  \:  \: y = f(x) \\ s =  \int \:  \sqrt{ ({dx)}^{2}  + ( {dy}) {}^{2}  }  =  \int \:  \sqrt{1 +  (\frac{dy}{dx}) {}^{2}  } dx

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