Question

are all dimensionally correct equations numerically correct? give one example. ​

Answer 1

Answer:

❚⠀ ⠀No all dimensionally correct equations are not numerically correct because in the use of dimensions numerical constants are said to be dimensionless and thus we cannot specify if there is the need of numerical constants in the equations.

⠀ ⠀

21$<svg width="22" height="12" viewBox="0 0 100 100">\ \textless \ br /\ \textgreater \ \ \textless \ br /\ \textgreater \ <path fill="red"</p><p>d="M92.71,7.27L92.71,7.27c-9.71-9.69-25.46-9.69-35.18,0L50,14.79l-7.54-7.52C32.75-2.42,17-2.42,7.29,7.27v0 c-9.71,9.69-9.71,25.41,0,35.1L50,85l42.71-42.63C102.43,32.68,102.43,16.96,92.71,7.27z"></path>\ \textless \ br /\ \textgreater \ \ \textless \ br /\ \textgreater \ <animateTransform \ \textless \ br /\ \textgreater \ attributeName="transform" \ \textless \ br /\ \textgreater \ type="scale" \ \textless \ br /\ \textgreater \ values="1; 1.5; 1.25; 1.5; 1.5; 1;" \ \textless \ br /\ \textgreater \ dur="01s" \ \textless \ br /\ \textgreater \ repeatCount="40000"> \ \textless \ br /\ \textgreater \ </animateTransform>\ \textless \ br /\ \textgreater \ \ \textless \ br /\ \textgreater \ </svg>$$<svg width="8" height="18" viewBox="0 0 100 100">\ \textless \ br /\ \textgreater \ \ \textless \ br /\ \textgreater \ <path fill="Black"</p><p>d="M92.71,7.27L92.71,7.27c-9.71-9.69-25.46-9.69-35.18,0L50,14.79l-7.54-7.52C32.75-2.42,17-2.42,7.29,7.27v0 c-9.71,9.69-9.71,25.41,0,35.1L50,85l42.71-42.63C102.43,32.68,102.43,16.96,92.71,7.27z"></path>\ \textless \ br /\ \textgreater \ \ \textless \ br /\ \textgreater \ <animateTransform \ \textless \ br /\ \textgreater \ attributeName="transform" \ \textless \ br /\ \textgreater \ type="scale" \ \textless \ br /\ \textgreater \ values="1; 1.5; 1.25; 1.5; 1.5; 1;" \ \textless \ br /\ \textgreater \ dur="0.5s" \ \textless \ br /\ \textgreater \ repeatCount="40000"> \ \textless \ br /\ \textgreater \ </animateTransform>\ \textless \ br /\ \textgreater \ \ \textless \ br /\ \textgreater \ </svg>$ꜰᴏʟʟᴏᴡ » ɪɴʙᴏx

Answer 2

Concept Introduction: Dimensions are a good way finding a formula.

Explanation:

We have been Given: are all dimensionally correct equations numerically correct?

We have to Find: The correct answer.

No, the Dimensionally correct equation may or may not be numerically correct.

Example: If are of the circle is given as

$12 {r}^{2}$

But area is

$\pi {r}^{2}$

and it's dimensions is

${(l)}^{2}$

So due to the Constant the given area is Numerically not equal to the calculated but still they are Dimensionally correct.

Final Answer:

No, the Dimensionally correct equation may or may not be numerically correct.

No, the Dimensionally correct equation may or may not be numerically correct.Example: If are of the circle is given as

No, the Dimensionally correct equation may or may not be numerically correct.Example: If are of the circle is given as$12 {r}^{2}$

No, the Dimensionally correct equation may or may not be numerically correct.Example: If are of the circle is given as$12 {r}^{2}$But area is

No, the Dimensionally correct equation may or may not be numerically correct.Example: If are of the circle is given as$12 {r}^{2}$But area is $\pi {r}^{2}$

No, the Dimensionally correct equation may or may not be numerically correct.Example: If are of the circle is given as$12 {r}^{2}$But area is $\pi {r}^{2}$and it's dimensions is

No, the Dimensionally correct equation may or may not be numerically correct.Example: If are of the circle is given as$12 {r}^{2}$But area is $\pi {r}^{2}$and it's dimensions is ${(l)}^{2}$

No, the Dimensionally correct equation may or may not be numerically correct.Example: If are of the circle is given as$12 {r}^{2}$But area is $\pi {r}^{2}$and it's dimensions is ${(l)}^{2}$So due to the Constant the given area is Numerically not equal to the calculated but still they are Dimensionally correct.

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