Question

are rectangular Park has length 5m and breadth 4m if four square formed along the boundary of it what is the perimeter of figure
formed plss​

Answer 1

Answer:

Your answer is 61 m.

Step-by-step explanation:

Length of rectangular park = 5m

Breadth = 4m

Area of park = l×b

= 5×4

=20m

Side of 1st square = 5m (Consider length of rectangle )

Area = s×s

= 5×5

=25m

Side of 2nd square = 5m

Area = s×s

= 5×5

=25m

Side of 3rd square = 4m ( Consider breadth of rectangle )

Area = s×s

= 4×4

=16m

Side of 4th rectangle = 4m

Area = s×s

= 4×4

=16m

Area of total area = Area of rectangle+(Area of 1st square+Area of 2nd square)+

(Area of 3rd square + Area of 4th square)

= 20 + 25 + 16

= 45+16

= 61m Answer

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Answer 2

Answer:

The perimeter of figure is 72 m.

Step-by-step explanation:

Given,a rectangular park has length is 5 m and breadth is 4 m.

and it is also given four square formed along the boundary of the parl.

Now we know the park is rectangular.

So,the park has two length and two breath.

And according to question two square is formed by length which is equal to 5 m and two square is formed by breath which is equal to 4 m.

We know, perimeter of square $= 4 \times side$

Here two square has side 5 m

So, total perimeter of those two square

$= 2 \times 4 \times sides \\ = 2 \times 4 \times 5 \\ = 40 \: m$

Again two square has side 4 m.

So,total perimeter of those two square

$= 2 \times 4 \times 4 \\ = 32 \: m$

Therefore total perimeter of all square = total perimeter of the figure

$= (40 + 32) \: m \\ = 72 \: m$

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